Three consecutive even numbers have a sum between 84 and 96. write an inequality to find the three numbers. let n represent the smallest even number. solve the inequality

The numbers are: n, (n+2) and (n+4);
we can suggest this inequation:
84<n+(n+2)+(n+4)<96

Now, we solve this inequation:
84<n+(n+2)+(n+4)<96
84<3n+6<96

1)
3n+6>84
3n+6-6>84-6
3n>78
3n/3>78/3
n>26

2)
3n+6<96
3n+6-6<96-6
3n<90
3n/3<90/3
n<30

The solution is:
26<n<30

Then: n=28

The numbers will be: 28,30 and 32.

The first option would be correct if it were one half and not one