AJKL hasj = 7, k = 11, and mZJ = 18°. Complete the statements to determine all possible measures of angle K.
Triangle JKL meets the
criteria, which means it is the ambiguous case.
Substitute the known va Aas to the law of sines: sin(189) = sin(k)
ASA
Cross multiply: 11sin(1& SSA
Solve for the measure of angle K, and use a calculator to determine the value.
Round to the nearest degree: m2K
However, because this is the ambiguous case, the measure of angle K could also be
yº

step-by-step explanation:

hans did not square the 40-unit side; he merely multiplied it by 2.   incorrect.

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

mark brainliest and have a great day!

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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