Two solution of salt water contain 0.03% and 0.23 salt respectively. A lab technician
wants to make 1 liter of Solution which contains
0.18% salt. How much of each solution should
She use?
Amount of 0.3% solution-milliliter
Amount of 0.23% solution - Milliliter

Step-by-step explanation:

Let x represent the quantity (in liters) of the higher percentage solution, the 0.23% solution. Then 1-x will be the quantity of 0.03% solution. The amount of salt in the mix is ...

  0.23%·x +0.03%·(1 -x) = 0.18%·1

Multiply by 100% and subtract 3:

  20x = 15

  x = 15/20 = 0.75 . . . . liters of 0.23% solution

  1-x = 1-0.75 = 0.25 . . liters of 0.03% solution

The lab tech needs 750 mL of 0.23% solution and 250 mL of 0.03% solution.

i believe that the answer is

b. y-1=-2(x-4)

hope this !

486in is correct

step-by-step explanation: