El calor especifico del agua es de 4184 J/kg ·K ¿en cuantos joules cambia la energia interna de 50 g de agua cuando se calienta desde 21ºC hasta 37ºC? Suponga que la dilatacion del agua es despreciable el calor añadido para aumentar la temperatura del agua es AQ= cm Ar = (4184J/kg·K) (0.050 kg)(16ºC)=3.4x10´3J

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right

false

step-by-step explanation:

the reason i say this is because for a certain length of sides you can pick any two and the length is wither equal or greater than the third side and in this case it's not.

3 + 5 = 8

8 is smaller than 9 which is the third side.

hope this : )

oof

step-by-step explanation: