Ming throws a stone off a bridge into a river below.

The stone's height (in meters above the water), xxx seconds after Ming threw it, is modeled by:

h(x)=-5(x-1)^2+45h(x)=−5(x−1)

What is the maximum height that the stone will reach?

what is the meters

We have been given that Ming throws a stone off a bridge into a river below.

The stone's height (in meters above the water), x seconds after Ming threw it, is modeled by .

We are asked to find the maximum that the stone will reach.

We can see that our given equation is in vertex form of parabola with vertex at point (h,k).

We can also see that leading coefficient is negative, so our given parabola is a downward opening parabola and its maximum value be at vertex.

The maximum height will be equal to y-coordinate of vertex.

We can see that vertex of our given parabola is at point (1,45). Therefore, the maximum height will be 45 meters.

the image is given below

since the options are not given so we draw it from the equation

the given equation is

y = (x-1) (x+4)

y = y² + 3x - 4

the above equation is a quadratic equation which will have two roots. if we draw the graph for it, it will look like this