Mathematics, 06.05.2020 20:33 plum65
A survey of 1000 air travelers 1 found that 60% prefer a window seat. The sample size is large enough to use the normal distribution, and a bootstrap distribution shows that the standard error is SE = 0.015. Use a normal distribution to find a 99% confidence interval for the proportion of air travelers who prefer a window seat.
Round your answers to three decimal places. The 99% confidence interval is to .
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A survey of 1000 air travelers 1 found that 60% prefer a window seat. The sample size is large enoug...
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