What is the approximate volume of a cone with a height of 9 ft and radius of 3 ft?

Use 3.14 to approximate pi, and express your final answer to the nearest hundredth.

V=πr^2h/3=π·3^2·9/3≈84.823ft³      (SO..V≈84.82ft³)

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∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°