In ΔHIJ, the measure of ∠J=90°, the measure of ∠I=29°, and JH = 88 feet. Find the length of IJ to the nearest tenth of a foot.

We have been given that in ΔHIJ, the measure of ∠J=90°, the measure of ∠I=29°, and JH = 88 feet. We are asked to find the length of IJ to the nearest tenth of a foot.

First of all, we will draw a right triangle using our given information as shown in the attachment.  

We can see that in triangle HIJ, the side IJ is adjacent side to angle I and JH is opposite side to angle I.

We know that tangent relates opposite side of right triangle to adjacent side.

Upon rounding to nearest tenth, we will get:

Therefore, the length of the side IJ is approximately 258.8 units.

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.

i'm sorry i don't know

step-by-step explanation: