Determining the Vertex of a Parabola from Its Graph
On a coordinate plane, a parabola opens up with solid circles along the parabola at (negative 6, 5), (negative 5, 0), (negative 4, negative 3), (negative 3, negative 4), (negative 2, negative 3), (negative 1, 0), (0, 5).

What is the vertex of the parabola in the graph?

(
,
)

(-3, -4)

Step-by-step explanation:

The solid circles along the parabola are:

(-6, 5), (-5, 0), (-4, -3), (-3, -4), (-2, -3), (-1, 0), (0, 5).

Although on observation, the minimum point of y occurs at (-3, -4), we can also confirm through the function.

The x-intercept of the parabola are -5 and -1.

x=-5 or x=-1

x+5=0 or x+1=0

(x+5)(x+1)=0

The Vertex of the equation occurs at the axis of symmetry,

In

Axis of Symmetry,

Therefore, we can confirm that the vertex is (-3,-4) as stated earlier.

2 equivalent expressions to represent the area of a rectangle and the top is n-3 and the side is 2

area of the rectangle = length * width

given length = n - 3

width = 2

replace it in the area

so area of the rectangle = (n-3) *2

= 2(n-3)

one of the expression is 2(n-3)

to get another expression we distribute 2 inside the parenthesis

2(n-3) is 2n - 6

so another expression is 2n - 6

two equivalent expression are

2(n - 3)   , 2n - 6