Mathematics, 06.05.2020 02:39 daverius3153

Some students checked 6 bags of Doritos marked with a net weight of 28.3 grams. They carefully weighed the contents of each bag, recording the following weights (in grams): 29.2, 28.5, 28.7, 28.9, 29.1, 29.5. The average weight is 29.0 and the standard deviation is 0.36. Assume the weight of the bags follows normal distribution. Does this provide strong evidence that the true weight is not 28.3 grams?

Answers: 3

Show answers

Answers

Answer from: denarreiahspen5921

We conclude that the true mean weight is not 28.3 grams at 5% significance level.

Step-by-step explanation:

We are given that some students checked 6 bags of Doritos marked with a net weight of 28.3 grams.

They carefully weighed the contents of each bag, recording the following weights (in grams): 29.2, 28.5, 28.7, 28.9, 29.1, 29.5. The average weight is 29.0 and the standard deviation is 0.36.

Let $\mu$ = true mean weight of bag.

So, Null Hypothesis, H_0 : $\mu$ = 28.3 grams {means that the true mean weight is 28.3 grams}

Alternate Hypothesis, H_A : $\mu$ $\neq$ 28.3 grams {means that the true mean weight is not 28.3 grams}

The test statistics that would be used here One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ t_n_-_1

where, $\bar X$ = sample mean weight = 29.0 grams

s = sample standard deviation = 0.36 grams

n = sample of bags = 6

So, test statistics = $\frac{29.0-28.3}{\frac{0.36}{\sqrt{6} } }$ ~ t_5

= 4.763

The value of t test statistics is 4.763.

Since, in the question we are not given the level of significance so we assume it to be 5%. Now, at 5% significance level the t table gives critical values of -2.571 and 2.571 at 5 degree of freedom for two-tailed test.

Since our test statistics does not lie within the range of critical values of t, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the true mean weight is not 28.3 grams.

Answer from: Quest

the answer is here: : )

If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g - 1)(3)? 06-3-(4 + 3)2 6-3-(4-

Answer from: Quest

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

$\frac{sb}{cs}$ = $\frac{ra}{cr}$ ← substitute values

$\frac{4x+1}{2x}$ = $\frac{13.5}{6}$ ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2

Other questions on the subject: Mathematics

Mathematics, 21.06.2019 15:00, giraffegurl

Translate the word phrase into a math expression. 15 fewer than the product of 4 and a number. (pls immediately)

Answers: 2

continue

Mathematics, 21.06.2019 17:00, krharris

Drag the tiles to the correct boxes to complete the pairs. match the cart-coordinates with their corresponding pairs of y-coordinates of the unit circle

Answers: 3

continue

Mathematics, 21.06.2019 20:30, dominaricann2451

When you have 25 numbers, and jake picks 3 random numbers and puts them back, what is the chance bob has of picking those 3 numbers when he picks 6 random numbers (without putting them back)? explain.

Answers: 1

continue

Mathematics, 22.06.2019 01:20, love0000

Describe how to determine the average rate of change between x = 4 and x = 6 for the function f(x) = 2x^3 + 4. include the average rate of change in your answer.

Answers: 3

continue

You know the right answer?

Some students checked 6 bags of Doritos marked with a net weight of 28.3 grams. They carefully weigh...