If AD = 20 centimeters, DC = 15 centimeters,
BC = 7 centimeters, and AB = 24 centimeters,
what is the area of quadrilateral ABCD?

Incomplete question, check attachment for diagram of the question

Step-by-step explanation:

Given that,

AD = 20cm

DC = 15cm

BC = 7cm

AB = 24cm

Since the shape consist of two right angle triangle,

Then, we will find the area of each triangle and add them together to find the area of the quadrilateral ABCD

Area of a triangle can be calculated using

A = ½b×h

Then,

For triangle 1, its area is

A_1 = ½ × DC × AD

A_1 = ½ × 15 × 20

A_1 = 150 cm²

Fro triangle 2

A_2 = ½ × BC × AB

A_2 = ½ × 7 × 24

A_2 = 84 cm²

Then, the total area is

A = A_1 + A_2

A = 150 + 84

A = 234 cm²

Area of the quadrilateral ABCD is 234cm²

kk.bj.

step-by-step explanation:

.mnm.kn.kj

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6