Find the equation of the line that is perpendicular to y = – 1 3 x + 2 and passes though the point (–5, 2).

Step-by-step explanation:

eq . of line is y=-13 x+2

or 13 x+y=2

eq. of   any line perpendicular to above line is

x-13y=c

because it passes through (-5,2)

-5-13(2)=c

c=-31

x-13y=-31

13y=x+31

y=1/13  x  +31/5