Garrett throws a dart at a circular dartboard. The dartboard has a radius of 18 inches, and the bull’s eye in the center of the dartboard has a radius of 4 inches. What is the probability that a dart thrown at random within the dartboard will bit the bull’s eye. Round your answer to the nearest tenth, if necessary.

A. 20.3%
B. 4.9%
C. 22.2%
D. 4.5%

I think it's 4.9%

Step-by-step explanation:

I got this from another website so bare with me if this is wrong.

"Find the area of the board (this will be your sample space)

and area covered by the bull's eye (this will be numerator for calculating probability)

area of circle = πr^2

for the board, radius = 18

for the bull's eye, radius = 4

4^2π/18^2π

Pi gets canceled out

Multiply what you have left by 100

4^2/18^2 * 100 = 4.938% or 4.94% which can be rounded to the nearest tenth, which is 4.9%

50-38=12

step-by-step explanation:

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!