Find a 99% prediction interval for the wardrobe expenditure for an individual student who has debt of $70,000 and has a graduation GPA of 3.2. Explain its meaning relative to the problem. Compare the width of this interval to that of the interval calculated in the previous part of the problem. Give a reason for any difference in the width of this interval and the one you found in the previous part of the problem.

3,000,540

step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

dont trust me im no expert these losers made me fail a test bro this sucks

step-by-step explanation:

236 cm 16 time 12 = 192

6 times 7 = 42

192+42