A rural mail carrier logged the mileage on the odometer at the start of the mail route as 31,500 miles. After 6.5 hours, the carrier returned the truck and recorded the mileage at 31,713 miles. What was the average velocity of the mail truck? Explain your reasoning.

The average velocity of the mail truck after traveling such distance is 9,275.1 miles per hour

Given'

Distance 1 = 31,500 Miles

Distance 2 = 31,713 miles

Total time taken = 6.5 hours

Average velocity = Total distance ÷ Total time

= (Distance 1 + Distance 2) ÷ Total time taken

= (31,500 + 31,713) ÷ 6.5

= 63,213 ÷ 6.5

= 9725.0769230769

Approximately, 9,275.1

Therefore, average velocity of the mail truck is 9,275.1 miles per hour

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Step-by-step explanation:

Average speed = total distance / total time taken

Average speed is the total distance traveled divided by the total time taken

The carrier first odometer route is

d_1 = 31,500 miles

On return of the truck, the odometer reads

d_2 = 31,713 miles

The total time taken is 6.5 hours on return

Then,

Average Speed = total distance / total time.

A.V = (d_1 + d_2) / t

A.V = (31,500 + 31713) / 6.5

A.V = 63213 / 6.5

A.V = 9725.1 mile per hour

A.V = 9725.1 mph

27 + 13x + 15 = (x + 5)( =

step-by-step explanation:

27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( =