If the mean weight of 3 outfielders on the baseball team is 194 lb and the mean weight of the 6 other players is 229 lb, what is the mean weight of the 9-person team?

217.33 Ib

Step-by-step explanation:

The mean of a set of numbers is the ratio of the total of these numbers to the number of numbers added. As such where there are x numbers and the sum of these numbers is T, the mean is

= T/x

If the mean weight of 3 outfielders on the baseball team is 194 lb, the total weight  of the 3 outfielders

= 194 * 3

= 582 Ib

the mean weight of the 6 other players is 229 lb, the total weight  of the 6 outfielders

= 229 * 6

= 1374 Ib

Total weight of the 9 players

=  1374 Ib + 582 Ib

= 1956 Ib

Mean of 9 person team

= 1956/9

= 217.33 Ib

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

-9

step-by-step explanation: