Given that
log
4
(
t
)
=
−
6.64
,
log
4
(
z
)
=
−
19.2
, and
log
4
(
y
)
=
3.1
, find the following:

51.35

Step-by-step explanation:

We want to evaluate:

log  [7throot( z^10)] /((t^2) * y^12)   (base 4) = ?

log  [7throot( z^10)] /((t^2) * y^12)   (base 4) =

log [ (z^(10/7) ) / ( (t^2) * y^12 )  (base 4) =

log [z^(10/7)]  (base 4)  -  log ( (t^2) * y^12)  (base 4)

=  (10/7)* log z (base 4)  -  log (t^2) (base 4) -  log (y^12) (base 4)

=  (10/7) log z  - log (t^2) - log (y^12)      leave out the (base 4) to understand that this is a log with base 4

= (10/7) log z -  2*log t  -  12 log y

we know log t = -6.64  ,   log z = -19.2,    log y = 3.1

We plug in.

so.

expression = (10/7)* (-19.2)  - 2*(-6.64)  - 12*(3.1)

=  -27.42857  +  13.28  - 37.2

=-51.34857

about  51.35

4096 bacteria

step-by-step explanation:

i you goofed up when writing this, because hnot is not a word minusf is not either. i cannot answer   because of that.

step-by-step explanation: