If you roll a fair die two times, what is the probability of rolling an odd number then rolling a 6 on the same die?

P (6+odd) = 1/3

Step-by-step explanation:

In this situation, rolling a six-sided has 6 outcomes, each of which is equally likely, so we can define the probability of an event (such as rolling a 6 or rolling an odd number) as the ratio of favorable outcomes to possible outcomes: the probability of rolling a 6 and the probability of rolling an odd number We often write P(roll a 6) = 1/6 to stand for "the probability that you roll a 6 is equal to 1/6" where P(E) means the probability that event E occurs. (This is like function notation in algebra: the parentheses do not mean multiplying P times E in this situation.) We might also write P(6) instead of P(roll a 6) as long as the context is clear (that we're rolling a single six-sided die and looking to get a 6.)

In practice, even if a die is absolutely fair (and few dice truly are), we might roll the die 12 times (say) and not get any sixes. Or we might get 4 sixes instead of the 2 sixes we'd expect to get. But if rolled the dice a million times, or a billion times, we would expect the percentage of rolls resulting in sixes would eventually settle in on 1/6.

Answer

1/6, or 16.67%, for rolling 6 + 3/6 for rolling an odd number prior.

Meaning same chance if it is the other way round with odds then throwing a 6.

P 1/6+3/6 = 4/12 = 1/3 chance. = 33.33%

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