Mathematics, 05.05.2020 01:39 kellimcollier8294

You are the manager of a restaurant for a fast-food franchise. Last month, the mean waiting time at the drive-through window for branches in your geographical region, as measured from the time a customer places an order until the time the customer receives the order, was 3.9 minutes. You select a random sample of 64 orders. The sample mean waiting time is 4.03 minutes, with a sample standard deviation of 0.8 minutes. Complete parts (a) and (b) below.
a. Determine the test statistic.(two decimal places)
b. Find the p-value.(three decimal places)
c. What is the conclusion?

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Answer from: Svetakotok

(a) The test statistics is 1.30.

(b) The P-value is 0.198.

Step-by-step explanation:

We are given that the mean waiting time at the drive-through window for branches in your geographical region, as measured from the time a customer places an order until the time the customer receives the order, was 3.9 minutes.

You select a random sample of 64 orders. The sample mean waiting time is 4.03 minutes, with a sample standard deviation of 0.8 minutes.

Let $\mu$ = mean waiting time at the drive-through window for branches in your geographical region.

So, Null Hypothesis, H_0 : $\mu$ = 3.9 minutes {means that the mean waiting time was equal to 3.9 minutes}

Alternate Hypothesis, H_A : $\mu\neq$ 3.9 minutes {means that the mean waiting time was different from 3.9 minutes}

The test statistics that would be used here One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ t_n_-_1

where, $\bar X$ = sample mean waiting time = 4.03 minutes

s = sample standard deviation = 0.8 minutes

n = sample of orders = 64

So, test statistics = $\frac{4.03-3.9}{\frac{0.8}{\sqrt{64} } }$ ~ t_6_3

= 1.30

(a) The value of t test statistics is 1.30.

(b) The P-value of the test statistics is given by;

P-value = P( t_6_3 > 1.30) = 0.099

For two tailed test, p-value is calculated as = 0.099 $\times$ 2 = 0.198

Now, P-value of the test statistics is more than the level of significance as 0.198 > 0.05, so we have insufficient evidence to reject our null hypothesis.

Therefore, we conclude that the mean waiting time was equal to 3.9 minutes.

Answer from: Quest

idk

step-by-step explanation:

What is the graph of the rational function? y = x ^2 - 4x + 3 / x ^2 - 9

Answer from: Quest

Answer: c. x y2 04 66 16

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You are the manager of a restaurant for a fast-food franchise. Last month, the mean waiting time at...