Which is the equation of a parabola with Vertex (0, 0) and focus (-3, 0)?

-12x = y^2

Step-by-step explanation:

Notice that the vertex and the focus are both located on the horizontal line y = 0 (that is, on the x-axis).

Because the focus is to the left of the vertex, we know that the parabola opens left.

The distance between focus and vertex is 3 units.

We'll adapt this equation:  4px = y^2.  Here p is -3:

                                         4(-3)x = y^2, or

-12x = y^2

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.

the answer is two. hope this !