Factor By Grouping: 12a^(3)-9a^(2)+4a-3
(I need help with solving this problem. Please if you are able to answer this step by step, keep it as simple as you can. I have tried getting other help but no luck, just confusing and frustrating ways on how to solve this problem. If you do solve this problem, THANK YOU SO MUCH.)

We have been given an expression . We are asked to factor the given expression by grouping.

First of all, we will make two groups of our expression as:

Now we will factor of greatest common factor from each group.

Now we will factor out common terms as:

Therefore, the factorized form of our given expression would be .

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

graph them on a graphing calculator, press 2nd trace. select intersect. hit enter until it says answer. ti 84 works best

step-by-step explanation: