The decline of salmon fisheries along the Columbia River in Oregon has caused great concern among commercial and recreational fishermen. The paper 'Feeding of Predaceous Fishes on Out-Migrating Juvenile Salmonids in John Day Reservoir, Columbia River' (Trans. Amer. Fisheries Soc. (1991: 405-420) gave the accompanying data on 10 values for the data sets where y = maximum size of salmonids consumed by a northern squaw fish (the most abundant salmonid predator) and x = squawfish length, both in mm. Here is the computer software printout of the summary:

Coefficients:
Estimate Std. Error t value Pr(> |t|)
(Intercept) −90.020 16.710 −5.387 0.000
Length 0.705 0.048 14.566 0.000

Using this information, compute a 95% confidence interval for the slope.

Check the explanation

Step-by-step explanation:

sample size n=                                          10  

number of independent variables p=        1  

degree of freedom =n-p-1=                        8  

estimated slope b=                                   0.71  

standard error of slope=sb=                  0.0480

for 95 % confidence and 8 degree

of freedom critical t=                                  2.31

95% confidence interval =

b1 -/+ t*standard error=                          (0.6,0.82)

ye

step-by-step explanation:

sinn is the total amount of students now and m were the students before, you subtract them both (n-m) and divide that by m. then, since to get a percentage from a fraction you have to multiply by 100, your answer should look like this: n-m/m*100

step-by-step explanation: