I NEED HELP help me get the answer

a. P(odd sum)

OK, each is drawing from a pile of 2 even cards and one odd, so have a 2/3 chance of picking even and a 1/3 chance of picking odd.

1/3 × 1/3 = 1/9 probability of odd+odd = even

1/3 × 2/3 = 2/9 prob of odd + even = odd

2/3 × 1/3 = 2/9 prob of even + odd = odd

2/3 × 2/3 = 4/9 prob of even+even = even

Total odd: 2/9+2/9 = 4/9

a) 4/9

b. P(sum < 11)

Let's just work out all the possibilities and count.

1st 2nd sum

4  4  8

4 5  9

4 6 10

5 4 9

5 5 10

5 6 11

6 4 10

6 5 11

6 6 12

I count 6 of 9 are less than 11, so P=6/9 or

b)  2/3

the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

the root or roots of a polynomial are the values of the variable that makes the polynomial equal to 0. we can find the roots of a polynomial making the expression equal to 0 and then, isolating the variable (it it has just one variable).

for example, given the following polynomial:

the root or zero of the polynomial, can be found by making the expression equal to 0, and then, isolating the variable, so, finding the root we have:

therefore, we have that the root of the polynomial is equal to 2.

we must remember that the number of roots that a polynomial can have, will depend on the degree of the polynomial, a first degree polynomial have will have one single root, a second degree polynomial (quadratic expression) may have two roots and so.

hence the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

have a nice day!

the answer for the second equation is (4,0)