*plis need it* A cattle breeder sold ¾ of his cows. After that, he sold ¾ of the remainder, and there are 16 cows left. How many cows did he have at the beginning?

256 cows

Step-by-step explanation:

Let the total cow be a

3/4 of a

3/4 x a=3a/4

Remainder= a-3a/4=a/4

Remainder=a/4

3/4 Of The remainder

3/4 of a/4

3/4 x a/4=3a/16

New remainder will be

a/4-3a/16=a/16

New remainder is a/16

Therefore: a/16=16

Cross multiplying we get

a=16x16

a=256

- both graphs increase on their domain.

- the graphs of both functions have the same x-intercept.

- neither graph has a y-intercept.