What is the center of the circle given by the equation (x-3)2 + (y-9)2 = 16?
A. (-9,-3)
B. (-3,-9)
C. (3,9)
D. (9,3)

The center is (3,9) and the radius is 4

Step-by-step explanation:

We can write the equation for a circle as

(x-h)^2 + (y-k)^2 = r^2

Where (h,k) is the center and r is the radius

(x-3)^2 + (y-9)^2 = 4^2

The center is (3,9) and the radius is 4

C

Step-by-step explanation:

(x-a)^2 + (y-b)^2 = r^2

(a,b) = Center

r = radius

SO...

That means the center of the circle " (x-3)^2 + (y-9)^2 = 16" is...

(3,9) (C)

the answer for this question is : 360°

step-by-step explanation:

we have been given a triangle   we need to tell which one of these is a triangle below to map onto itself.

360° rotation is the complete rotation which eventually leads to the same figure which is given.

the correct will be, that is 360° that will cause the triangle below to map onto itself.

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value