A population of coyotes in a country is represented by the equation w(t)=80(0.98)^t, where t is the number of years since 1998. In what year will the population be 50 wolves?

2021

Step-by-step explanation:

w(t) = 80(0.98)^t

w(t) = 50

50/80 = (0.98)^t

5/8 = (0.98)^t

log(5/8) = log((0.98)^t)

Property of logs allows the exponent to be move to the front so,

log(5/8) = t*log(0.98)

solve for t

t = (log(5/8))/(log(0.98))

so t = 23.264

1998 + t = 2021.264

Round to 2021 because that's they year it is present in.

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c

96 39 cause 135 -96=39 im smart (i used a calculater)