Which of these strategies would eliminate a variable in the system of equations?
(2x + 8y = -3
3x + 6y = -4

Step-by-step explanation:

2x + 8y = -3  (1)

3x + 6y = -4 (2)

To eliminate a variable in the system of equations, we will follow the steps below;

To eliminate the x variable:

we multiply through equation(1) by 3   and  multiply through equation (2) by 2

6x +24y = -9 (3)

6x + 12y = -8 (4)

Next, is to subtract equation (2) from equation (1)

(This will cause the x variable to be eliminated)

6x-6x = 0    24y - 12y = 12y      -9--8=-9+8=-1

12 y  =  -1

or

To eliminate the y variable

we will;

Multiply through equation (1)   by 6    and multiply through equation (2) by 8

12x  + 48y  =  -18 (5)

24x  +48y    = -32 (6)

subtract equation (5) from equation (6)

This will cause the y variable to be eliminated

That is;

24x - 12x = 12x                48y-48y=0  -32--18 = -32+18 =-14

12x = -14

step-by-step explanation:

i am not sure sorry : c

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b