Jalen Brunson is shooting free throws. Making or missing free throws doesn't change the probability that he will make his next one, and he makes his free throws 90% percent of the time. What is the probability of Jalen Brunson making his next 2 free throw attempts?

The probability is 0.81

Step-by-step explanation:

In this question, we are tasked with calculating the probability that Jalen makes his next two free throws.

P(of making free throw) = 90% = 90/100 or 0.9

P(of missing free throw) = 1 - P( of making free throw) = 1-0.9 = 0.1

Now we want to calculate that probability of making the next two free throws.

That would be = p( of making next throw) * p(of making next two throws) = 0.9 * 0.9 = 0.81

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".