The value V(t) of a $25,000 car after t years that depreciates at 25% per year is given by the formula V(t) = V0(b)t. What is the value of V0 and b, and what is the car's value after 5 years (rounded to the nearest cent)?

Hint: Use the equation b = 1 − r to determine depreciation.

V0 = $25,000, b = 0.25, and the value after 5 years is $18,750.00
V0 = $25,000, b = 0.75, and the value after 5 years is $5,932.62
V0 = $25,000, b = 1.25, and the value after 5 years is $76,293.95
V0 = $25,000, b = 0.75, and the value after 5 years is $5,872.60

answer: 2 litters juice bottle

half of a gallon is 50% of a full gallon 2 litters of juice is 52% of a full gallon

hope this ^_^

x + 4/7

step-by-step explanation:

use cymath

i use my brain for prombles like this maybe you could try it

step-by-step explanation:

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form