Solve for x: x^2 + 14x + 49

-7twice

Step-by-step explanation:

This is a question on root of quadratic equation. The interpretation of the question

x² 14x + 49 is

x² + 14x + 49 = 0.meaning that we are to find two possible values for x that will make the expression equal 0.

We can use any of the methods earlier taught. For the purpose of this class, I am using factorization methods

x² + 14x + 49 = 0

Now, find the product of the first and the last terms, is

x² × 49 = 49ײ

Now find two terms such that their productbis 49x² and their sum equals 14x, the one in the middle.

We have several factors of 49x² but only one will give sum of 14x. Because of the time, I will only go straight to the required factors .

49x² = 7x × 7x and the sum gives 14x the middle terms..

Now we now replace the middle one by the factors and then factorize by grouping.

x² + 14x + 49 = 0

x² + 7x + 7x + 49 = 0

x(x + 7) + 7(x + 7) = 0

(x + 7)(x + 7). = 0

Now to find this value of x,

x + 7 = 0

x. = -7twice.

The root of the equation = -7twice.

hope this .

r3t40

1e+27

step-by-step explanation: