How many real solutions does x2+6x+13=0 have?

There are NO real solutions to this equation as per the study of its discriminant.

Step-by-step explanation:

In order to answer the question, one needs to examine the "discriminant" associated with this quadratic equation.

Recall that the discriminant of a quadratic equation of the form:

is given by:  

in our case :  

Then the discriminant becomes:

The discriminant is then a negative number, which means that there are NO real solutions (its solutions must involve imaginary numbers)

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,