Zahra wants the equation below to have an infinite number of solutions when the missing number is placed in the box.

Box (x minus 3) + 2 x = negative (x minus 5) + 4

c = -3

Step-by-step explanation:

Call the unknown c

c(x-3) +2x = -(x-5) +4

Distribute the negative sign

c(x-3) +2x = -x+5+4

Combine like terms

c(x-3) +2x = -x +9

Subtract 2x from each side

c(x-3) +2x-2x = -x-2x +9

c(x-3) = -3x+9

Factor a -3 from the right side

c(x-3) = -3(x-3)

Divide by (x-3)

c = -3

The right and left hand side need to be equal for there to be infinite solutions, so c = -3

2? if not the correct answer you might need to provide more information

step-by-step explanation: