The point (0.28, 0.96) lies on the unit circle. What is the tangent of an angle drawn in standard position whose terminal ray passes through this point?

Step-by-step explanation:

Given that the point that lie on the circle is

P = (0.28, 0.96)

Check attachment for understanding of the diagram

Generally

P = (sinθ, Cosθ)

Therefore, compare this with the given data,

Sinθ = 0.28

Cosθ = 0.96

So, the tangent drawn will be

Tan θ = opposite / adjacent

Tan θ = Sinθ / Cosθ

Tan θ = 0.28 / 0.96

Tan θ = 0.2917

θ = arcTan(0.2917)

θ = 16.26°

The tangent of the angle drawn is 16.26°

You can as well use the trigonometry formula,

So, from the attachment,

Tan θ = opposite / adjacent

Tan θ = 0.28 / 0.96

Tan θ = 0.2917

θ = arcTan(0.2917)

θ = 16.26°

for the points! : )