What is the distance between (9,1) to (1,8)

The distance between (9,1) to (1,8) is 3.26

Step-by-step explanation:

To solve this exercise we first have to calculate the distances between the factors of x and those of y

(x , y)

P1 = (9 , 1)

P2 = (1 , 8)

To calculate the distance we have to do P1 - P2

(9 , 1) - (1 , 8)

we subtract the corresponding from each other

9 - 1 = 8

1 - 8 = -7

(8 , -7)

Now that we have obtained these values, what we have to do is Pythagoras, since x represents a horizontal displacement, and y represents a vertical one, and the distance will be the hypotenuse that is formed from them.

h² = 8² + (-7)²

h² = 64 + 49

h² = 113

h = √113

h = 3.26

The distance between (9,1) to (1,8) is 3.26

i think it will be zero as slope has a formula of difference between initial and final distance divided by itz time interval