Write the equation to represent a line that contains the point (3, 5) and a slope of 2.

try to do the equation from this example

Step-by-step explanation:  The point-slope equation is used when one point and the slope are known. It is:

y

−

y

1

=

m

(

x

−

x

1

)

,x-

where  

(

x

1

,

y

1

)

is the known point, in this case,  

(

2

,

5

)

, and  

m

is the slope, in this case  

m

=

3

.

Substitute the known values into the equation.

y

−

5

=

3

(

x

−

2

)

⇐

point-slope form

This equation can be further simplified.

y

−

5

=

3

x

−

6

Add  

5

to both sides.

y

=

3

x

−

6

+

5

Simplify.

y

=

3

x

−

1

⇐

slope-Intercept form:  

y

=

m

x

+

b

, where

m

is the slope, and  

b

is the y-Intercept.

graph{y-5=3(x-2) [-18.79, 8.62, -7.36, 6.35]}

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)

answer: 0

step-by-step explanation: the positive, like 5, + its opposite, like -5 would be 0

5+(-5)=0, or 5-5=0