Which of the following sets is a subspace of set of prime numbers P Subscript nℙn for an appropriate value of n? A. All polynomials of the form p(t)equals=aplus+bt squaredt2, where a and b are in set of real numbers Rℝ B. All polynomials of degree exactly 4, with real coefficients C. All polynomials of degree at most 4, with positive coefficients

Check the explanation

Step-by-step explanation:

A. All polynomials of the form p(t) = a + bt2, where a and b are in: This means that  A is closed under scalar mult and vector addition, and includes the zero vector.

B.All polynomials of degree exactly 4, with real coefficients: what this means is that under vector addition, B isn't closed, and it does not consist of the zero vector. What it consist of  is just polynomials with degree exactly 4. Let f=x4+1f=x4+1 and let g=−x4g=−x4. Both are in B, but their sum is not, because it has degree 0.

C. All polynomials of degree at most 4, with positive coefficients: what this means is that C is not a subspace for the reason that the positive coefficients make zero vector impossible. The restriction there also makes C not closed under multiplication by the scalar −1.

So the answer is only A :D

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

5x+10 is the correct one

hope this