Mathematics, 05.05.2020 07:23 tiffanyrenee3355

An urn contains two blue balls (denoted B1 and B2) and three white balls (denoted W1, W2, and W3). One ball is drawn from the urn, its color recorded, and is replaced. Another ball is then drawn and its color recorded. Let B1W2 denote the outcome that the first ball drawn is B1 and the second ball drawn is W2. Because the first ball is replaced before the second ball is drawn, the outcomes of the experiment are equally likely. List all 25 possible outcomes of the experiment on a sheet of paper.(a)Consider the event that the first ball that is drawn is blue. Count all the outcomes in this event. What is the total?Incorrect: Your answer is incorrect. What is the probability of the event?Incorrect: Your answer is incorrect.(b)Consider the event that only white balls are drawn. Count all the outcomes in this event. What is the total?Correct: Your answer is correct. What is the probability of the event?

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Answer from: gianababnnna

The probability that the first ball drawn is blue $\frac{2}{5}$ .

And Probability that only white balls are drawn; $\frac{9}{25}$

Given that,

An urn contains two blue balls (denoted B1 and B2)

And three white balls (denoted W1, W2, and W3).

One ball is drawn from the urn, its color recorded, and is replaced. Another ball is then drawn and its color recorded.

We have to determine,

Consider the event that the first ball that is drawn is blue. Count all the outcomes in this event.

According to the question,

Let, B1 W2 denote the outcome that the first ball drawn is B1 and the second ball drawn is W2. Because the first ball is replaced before the second ball is drawn, the outcomes of the experiment are equally likely.

List all 25 possible outcomes of the experiment .

An urn contains two blue balls $B_1, \ B_2$ and three white balls W_1 ,W_1, W_3

The possible outcomes are:

$B_1,B_1 \ B_1,B_2 \ B_1,W_1 \ B_1,W_2 \ B_1,W_3\\B_2,B_1 \ B_2,B_2 \ B_2,W_1 \ B_2,W_2 \ B_2,W_3\\W_1,B_1 \ W_1,B_2 \ W_1,W_1 \ W_1,W_2 \ W_1,W_3\\W_2,B_1 \ W_2,B_2 \ W_2,W_1 \ W_2,W_2 \ W_2,W_3\\W_3,B_1 \ W_3,B_2 \ W_3,W_1 \ W_3,W_2 \ W_3,W_3\\$

All the first ball drawn is blue,

Number of Outcomes =10

The probability that the first ball drawn is blue $= \dfrac{10}{25} = \dfrac{2}{5}$

The probability only white balls are drawn,

Number outcomes =9

Probability that only white balls are drawn; $= \dfrac{9}{25}$

To know more about Probability click the link given below.

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An urn contains two blue balls (denoted B1 and B2) and three white balls (denoted W1, W2, and W3). O

Answer from: sheram2010

$(a)\dfrac{2}{5}$

$(b)\dfrac{9}{25}$

Step-by-step explanation:

An urn contains two blue balls (denoted $B_1 \:and\: B_2$ ) and three white balls (denoted $W_1, W_2 \:and\: W_3$ ).

In the selection, a ball is picked and replaced.

From the attached probability tree, the possible outcomes are:

$B_1B_1,B_1B_2,B_1W_1,B_1W_2,B_1W_3\\B_2B_1,B_2B_2,B_2W_1,B_2W_2,B_2W_3\\W_1B_1,W_1B_2,W_1W_1,W_1W_2,W_1W_3\\W_2B_1,W_2B_2,W_2W_1,W_2W_2,W_2W_3\\W_3B_1,W_3B_2,W_3W_1,W_3W_2,W_3W_3$