Determine the set of interior points, accumulation points, isolated points, and boundary points for each of the following sets: (a) {1, 1/2, 1/3, 1/4, 1/5, . . . } (b) {0} ∪ {1, 1/2, 1/3, 1/4, 1/5, . . . } (c) (0, 1) ∪ (1, 2) ∪ (2, 3) ∪ (3, 4) ∪ · · · ∪ (n, n + 1) ∪ . . . (d) (1/2, 1) ∪ (1/4, 1/2) ∪ (1/8, 1/4) ∪ (1/16, 1/8) ∪ . . . (e) {x : |x − π| < 1} (f) {x : x 2 < 2} (g) R \ IN (h) R \ Q

One shot. if 60% of 10 is 6, then what is 70%? we know it would be seven (since 60% is mathematically 60/100, or 6/10, then 70% is 70/100, or 7/10) but we can check anyway using ratios: 6 : 60% = x : 70%*inverse multiplicationx * 60% = 6 * 70%*divide both sides by 60%x = (6 * 70%) / 60%x = 7and since he has made 6 shots already, he would need just one more to get 7 shots or 70%. if the explanation is too confusing, comment and i will try to

That is lot of hell