Watch News
35
Carol wanted to see how the data would change if she
did not include the outlier in her study. The results are
shown in the table with the outlier crossed out.
Find each listed value.
Classes
Mrs. Hall
Mr. Benny
Mr. Leggo
Ms. Talle
Miss Flower
Mrs. Gomez
Mrs. Range
Ms. Book
Mr. Toledo
45
26
32
46
Range =
Median =
38
39
40
26
Lower quartile and upper quartile =
Interquartile range =
Which value was affected the most?

Ok here we go ..there are plenty of ways to solve such math problems but we will go for the smartest and easiest ..5x+2y=7  -2x+6y=9we rearrange them into the following ..by multiplying the 1st equation by 2 it becomes 10x + 4y = 14we rearrange it and so it becomes 10x = 14 - 4yas for the second equation we multiply it by 5 and rearrange it so it becomes as to the following ..-10x + 30y = 45rearranging so 10x = 30y -45now 10x equals both 14 - 4y and 30y -45so   14 - 4y = 30y -4531 = 26yy= 31/26 = 1.19 or around 1.2so by now we can calculate x easily as  -2x+6y=9so 2x = 6y -9 = 6 * 31/26 - 9 = -1.84  then x = - 0.92 or around -0.9best luck!