Glve the values of a, b, and c from the standard form of the equation (2x + 1)(x - 2) =0

Prove (a) cosh2(x) − sinh2(x) = 1 and (b) 1 − tanh 2(x) = sech 2(x). solution (a) cosh2(x) − sinh2(x) = ex + e−x 2 2 − 2 = e2x + 2 + e−2x 4 − = 4 = . (b) we start with the identity proved in part (a): cosh2(x) − sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 − sinh2(x) cosh2(x) = 1 or 1 − tanh 2(x) = .

Aye asap pls ! markin da brainiest too ! btw da step choices are all add, distribute, divide, n subtract

Select the conic section that represents the equation. 3x2 + 3y2 -2x + 4 = 0