(n=1→[infinity]) Σ (n + 1)/ (n⁹ + n)
Mathematics, 05.05.2020 08:24 kevinvalencia01
Determine whether the series converges or diverges.
(n=1→[infinity]) Σ (n + 1)/ (n⁹ + n)
a) The series converges by the Comparison Test. Each term is less than that of a convergent geometric series.
b) The series converges by the Comparison Test. Each term is less than that of a convergent p-series.
c) The series diverges by the Comparison Test. Each term is greater than that of a divergent p-series.
d) The series diverges by the Comparison Test. Each term is greater than that of a divergent harmonic series.
Answers: 1
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Determine whether the series converges or diverges.
(n=1→[infinity]) Σ (n + 1)/ (n⁹ + n)
(n=1→[infinity]) Σ (n + 1)/ (n⁹ + n)
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