Find the area of the region under the graph of the function f on the interval [4, 8].
f(x) = 10/x^2

If you could show the steps and the answer, I would really appreciate it!

General Formulas and Concepts:

Calculus

Integration

Integration Rule [Reverse Power Rule]:                                                              

Integration Rule [Fundamental Theorem of Calculus 1]:                                    

Integration Property [Multiplied Constant]:                                                        

Area of a Region Formula:                                                                                    

Step-by-step explanation:

Step 1: Define

Identify

Step 2: Find Area

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°