A crane has a cable with a breaking strain of 6400 kg
measured to 2 significant figures.
It is used to lift crates which weigh 90 kg measured to the nearest 10 kg.
What is the greatest number of crates that can safely be lifted
at one time without breaking the cable?
Some working must be shown.

This question is based on the concept of division. Therefore, the the greatest number of crates that can safely be lifted  at one time without breaking the cable is 71.

Given:

A crane has a cable with a breaking strain of 6400 kg  measured to 2 significant figures.  It is used to lift crates which weigh 90 kg measured to the nearest 10 kg.

We need to calculate the greatest number of crates that can safely be lifted

at one time without breaking the cable.

According to the question,

It is given that, the breaking strain of the crane is 6,400 kilograms and each crate is 90 kilograms.

Thus, to know the number of crates (n) that can safely lift is equal to the weight of the crane is 6,400 kilograms divided by is 90 kilograms.

In mathematically expressed as,

Therefore, the the greatest number of crates that can safely be lifted  at one time without breaking the cable is 71.

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Step-by-step explanation:

According to the problem, the breaking strain of the crane is 6,400 kilograms.

Each crate is 90 kilograms. So, to know the number of crates we can safelty lift, we just need to divide.

Therefore, we can lift 71 crates without breaking the cable.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632