Which strategy would you choose to expand (x+11)(2x+3) and write an equivalent expression

Step-by-step explanation:

Given the expression (x+11)(2x+3)

We want to expand it and write equivalent expression

Generally if we want to expand an expression we will take one of the expression in one bracket and multiply with the other bracket and then take the other expression and multiply it with the other

E.g, (a+b) × (c + d)

Then, we take a × (c+d) and also b × (c+d)

We can do it the other way round too and it will give the same results.

So, applying this to the given expression

(x+11)(2x+3)

x(2x+3) + 11(2x+3)

2x² + 3x + 22x + 33

2x² + 25x + 33

Then, the equivalent expression is 2x² + 25x + 33

(x + 11)(2x + 3) = 2x² + 25x + 33

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !