6) The scatter plot below shows the temperatures (y), in degrees Fahrenheit (°F), that were recorded at different altitudes (x), in thousands of feet. Which equation could represent the line of best fit for the temperatures, in degrees Fahrenheit, based on the altitudes, in thousands of feet? A) y = −5x + 70 B) y = −10x + 70 Reactivate C) y = − 7 2 x + 60 D) y = − 9 2 x + 60

y = − (7 /2) x + 60 equation could represent the line of best fit for the temperatures, in degrees Fahrenheit, based on the altitudes, in thousands of feet

Step-by-step explanation:

Given:

A plot for temperature and altitude

(Refer the attachment)  .......FOR GRAPH

To Find:

Correct relationship between them

Solution:

By using  given relationship as we can conclude.

1)y=-5x+70:

Put y=0 then

5x=70

x=70/5

x=14

This value dont corresponds when y=0 in graph

2) y=-10x+70

put y=0 then

10x=70

x=7

This value dont corresponds when y=0 in graph very less than original value.

3)y=-(7/2)x+60

put y=0 then

(7/2)x=60

7x=120

x=120/7

x=17.14

This value  corresponds when y=0 in graph

4)y=-(9/2)x+60

Put y=0 then

(9/2)x=60

9x=120

x=120/9

x=13.33

This value dont corresponds when y=0 in graph which much less than original value.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

the expression (1.26)2t reveals the approximate rate of increases in the number of plants semiannually.

hope this : )