Abhishek is 6 years older than Jagadish. Six years ago Abhishek was twice as old as Jagadish. Write down the situation in algebraic expression and find how old is each now?

Abhishek is 18 years, Jagadish is 12 years.

Step-by-step explanation:

Let Abhishek present age be y

Let Jagadish present age be z.

Abhishek is 6 years older than Jagadish. This can be written as:

y = z + 6 equation i

Six years ago, Abhishek was twice as old as Jagadish. This can be written as:

y - 6 = 2(z-6)

y - 6 = 2z - 12

y = 2z - 12 + 6

y = 2z - 6 equation ii

From equation i and equation ii, equate the values of y together. This will be:

z + 6 = 2z - 6

Collect like terms

2z - z = 6 + 6

z = 12 years

This means that Jagadish is 12 years.

From equation I

y = z + 6

y = 12 + 6

y = 18 years

Abhishek is 18 years

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3