Find the perimeter and area of the figure.
5 m
12 m
The perimeter is
meters.
The area is
square meters.

p=30

a=30

Step-by-step explanation:

use pythagorean theorem to find the third side (you can use this bc its a right triangle)

5^2 + 12^2 = c^2

25+144=c^2

169=c^2

13=c

perimeter = 5 + 12 + 13 = 30

using heron's formula where s equals half the perimeter =15

square root[s(s-a)(s-b)(s-c)]

square root[15(15-5)(15-12)(15-13)]

square root[15(10)(3)(2)]

square root[900]

30

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0