A ladder 20 feet long leans against a building forming and angle of 46 degrees with the level ground. To the nearest foot how far away is the foot of the ladder to the building

The distance of the foot of the ladder to the building is 14 ft.

Step-by-step explanation:

The length of ladder = 20 ft

Angle formed by ladder with level ground, θ = 46

We are required to find out the distance of the foot of the ladder from the building

The above question can be found out by using trigonometric relations as follows;

The adjacent side of the right triangle formed by the ladder the building and the ground is the distance of the foot of the ladder from the building

The hypotenuse side is the length of the ladder = 20 ft

Therefore;

Adjacent side of triangle = Hypotenuse × cosθ

∴ Distance of the foot of the ladder from the building = Hypotenuse × cosθ

Distance of the foot of the ladder from the building = 20 ft × cos(56)

Distance of the foot of the ladder from the building = 13.893 ft

To the nearest foot, the distance of the foot of the ladder to the building = 14 ft.

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

answer4 to the second power is 16

and 4 to the third power is 64,