A presidential candidate plans to begin her campaign by visiting the capitals of 5 of the 50 states. If the five capitals are randomly selected without replacement, what is the probability that the route is Sacramento, Albany, Juneau, Hartford, and Bismarck, in that order?

The probability is 1/254,251,200

Step-by-step explanation:

We proceed as follows;

Firstly, we are selecting 5 state capitals out of 50. The number of ways we can do this is 50P5 = 50!/5!(50-5)! = 254,251,200 ways

Now, out of this number of ways , only one route is desired in that particular order.

This means the probability of having the route scheduled in that particular order would be;

1/254,251,200

0.000000003933

Step-by-step explanation:

As the candidate will visit the capitals of 5 of the 50 states, the probability of each capital being selected is 1/50.

As we want a probability of 5 specific capitals in a specific order, we can calculate the probability of each capital being chosed:

First city being Sacramento: Probability of 1/50

Second city being Albany: Probability of 1/49 (as the first city is not available now)

Third city being Juneau: Probability of 1/48

Fourth city being Hartford: Probability of 1/47

Fifth city being Bismarck: Probability of 1/46

So the final probability is 1/(50*49*48*47*46) = 0.000000003933

i can you with this sweetie!

step-by-step explanation:

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.