The lifespans of meerkats in a particular zoo are normally distributed. The average meerkat lives 10.410.410, point, 4 years; the standard deviation is 1.91.91, point, 9 years.

99.7%

Step-by-step explanation:

The lifespans of meerkats in a particular zoo are normally distributed. The average meerkat lives 10.4 years; the standard deviation is 1.9 years.

Use the empirical rule (68−95−99.7%) to estimate the probability of a meerkat living between 4.7 years and 16.1 years

The empirical rule states that almost all data fall within three standard deviations of the mean for a normal distribution. These are:

Given that:

mean (μ) = 10.4 years and standard deviation σ = 1.9 years

The first standard deviation ( μ ± σ) = (10.4 ± 1.9) = (8.5, 12,4). Therefore, 68% of data falls between 8.5 years and 12.4 years

The second standard deviation ( μ ± 2σ) = (10.4 ± 2×1.9) = (6.6, 14.2). Therefore, 95% of data falls between 6.6 years and 14.2 years

The third standard deviation ( μ ± 3σ) = (10.4 ± 3×1.9) = (4.7, 16.1). Therefore, 99.7% of data falls between 4.7 years and 16.1 years

the distance from any point on the parabola to the focus is the exact same as the distance from that point to the directrix.

if you could provide answer choices that might allow me to answer the question easier if my above answer isn't an option! (: